0=162(y^2)+5y-162

Solution for 0=162(y^2)+5y-162 equation:

0=162(y^2)+5y-162

We move all terms to the left:

0-(162(y^2)+5y-162)=0

We add all the numbers together, and all the variables

-(162y^2+5y-162)=0

We get rid of parentheses

-162y^2-5y+162=0

a = -162; b = -5; c = +162;
Δ = b2-4ac
Δ = -52-4·(-162)·162
Δ = 105001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{105001}}{2*-162}=\frac{5-\sqrt{105001}}{-324}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{105001}}{2*-162}=\frac{5+\sqrt{105001}}{-324}
$